Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

public class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int count = 0;
        int result = 0;
        for(int i=0;i<nums.length;i++){
            if(nums[i] == 1){
                count ++;
                if(count > result){
                    result = count;
                }                
            }
            if(nums[i] == 0){
                if(count > result){
                    result = count;
                }
                count =0;
            }
        }
        return result;
    }
}