Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7]
,
3 / \ 9 20 / \ 15 7
return its bottom-up level order traversal as:
[ [15,7], [9,20], [3] ]
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public List<List<Integer>> levelOrderBottom(TreeNode root) { Queue<TreeNode> nodes = new LinkedList<TreeNode>(); List<List<Integer>> res = new LinkedList(); if(root == null) return res; nodes.add(root); while(!nodes.isEmpty()){ List<Integer> sub = new LinkedList(); int num = nodes.size(); for(int i=0;i<num;i++){ TreeNode curr = nodes.poll(); sub.add(curr.val); if(curr.left != null) nodes.add(curr.left); if(curr.right != null) nodes.add(curr.right); } res.add(0,sub); } return res; } }