Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its bottom-up level order traversal as:
[ [15,7], [9,20], [3] ]
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<List<Integer>> levelOrderBottom(TreeNode root) {
Queue<TreeNode> nodes = new LinkedList<TreeNode>();
List<List<Integer>> res = new LinkedList();
if(root == null) return res;
nodes.add(root);
while(!nodes.isEmpty()){
List<Integer> sub = new LinkedList();
int num = nodes.size();
for(int i=0;i<num;i++){
TreeNode curr = nodes.poll();
sub.add(curr.val);
if(curr.left != null) nodes.add(curr.left);
if(curr.right != null) nodes.add(curr.right);
}
res.add(0,sub);
}
return res;
}
}
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