You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int extra = 0; ListNode curr1 = l1; ListNode curr2 = l2; ListNode res = new ListNode(0); ListNode ress = res; while(curr1 != null || curr2 != null){ if(curr1 == null){ ress.next = curr2; int tmp = curr2.val + extra; extra = 0; if(tmp >= 10){ tmp = tmp -10; extra = 1; } ress.next.val = tmp; ress = ress.next; curr2 = curr2.next; continue; } if(curr2 == null){ ress.next = curr1; int tmp = curr1.val + extra; extra = 0; if(tmp >= 10){ tmp = tmp -10; extra = 1; } ress.next.val = tmp; ress = ress.next; curr1 = curr1.next; continue; } int tmp = curr1.val +curr2.val + extra; extra = 0; if(tmp >= 10){ tmp = tmp -10; extra = 1; } ress.next = curr1; ress.next.val = tmp; ress = ress.next; curr2 = curr2.next; curr1 = curr1.next; } if(extra ==1){ ListNode extranode = new ListNode(extra); ress.next = extranode; ress = ress.next; } ress.next = null; return res.next; } }