Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

这道题我用了取巧的办法，排序，然后中间的数肯定是majority。顺便回忆了下快速排序的写法（这里没写）

还有个解法是用投票法，这里也贴出来了。（不是我写的）

public class Solution {
    public int majorityElement(int[] nums) {
        Arrays.sort(nums);
        return nums[nums.length / 2];        
    }
}

public class Solution {
    public int majorityElement(int[] num) {

        int major=num[0], count = 1;
        for(int i=1; i<num.length;i++){
            if(count==0){
                count++;
                major=num[i];
            }else if(major==num[i]){
                count++;
            }else count--;
            
        }
        return major;
    }
}